2019 Ram 2500 Laramie
VIN
3C6UR4FLLKG652075
This 2019 Ram 2500 Laramie is listed at $28,999 with 164,799 miles in Cornelia, GA.
Vehicle Decode
- Body
- Pickup
- Engine
- 6.7L · V6 · Diesel
- HP
- 370
- Drive
- 4x2
- Made by
- CHRYSLER DE MEXICO TOLUCA
Safety
- ✗ Backup camera
- ✗ Blind-spot monitor
- ✗ Lane departure
- ✗ ABS
- ✗ Electronic stability
Active listings
Full listing history on VehiSales →| Dealer | Location | Price | Mileage | Listed |
|---|---|---|---|---|
| Best Cars of Georgia 2 | Cornelia, GA 30531 | $28,999 | 164,799 mi | 2026-02-06 |
Former listings
| Dealer | Location | Price | Mileage | Listed |
|---|---|---|---|---|
| Best Cars of Georgia | Gainesville, GA 30504 | $33,999 | 164,799 mi | 2026-02-07 |
| Best Cars of Georgia | Gainesville, GA 30504 | $29,999 | 164,799 mi | 2026-02-07 |
| Best Cars of Georgia | Gainesville, GA 30504 | $32,999 | 164,799 mi | 2026-02-07 |
| Best Cars of Georgia | Gainesville, GA 30581 | $33,999 | 164,799 mi | 2026-02-06 |
| Best Cars of Georgia | Gainesville, GA 30504 | $31,999 | 164,799 mi | 2026-02-06 |
| Best Cars of Georgia | Gainesville, GA 30504 | $32,999 | 164,799 mi | 2026-02-06 |
| Best Cars of Georgia | Gainesville, GA 30504 | $29,999 | 164,799 mi | 2026-02-06 |
